luc077.c

Metadata

• Author — Amit Dutta
• Last updated — 08 Feb 2026
• License — MIT License (See the LICENSE file for details)

Problem Statement

Problem Statement

Write a program that receives an integer (less than or equal to nine digits in length) and prints out the number in words.

Source Code

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#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <ctype.h>

void convert(long, char *);

char *one[] = {
    "", "One ", "Two ", "Three ", "Four ", "Five ", "Six ", "Seven ", "Eight ", "Nine ", 
    "Ten ", "Eleven ", "Twelve ", "Thirteen ", "Fourteen ", "Fifteen ", "Sixteen ", 
    "Seventeen ", "Eighteen ", "Nineteen "
};

char *ten[] = {
    "", "", "Twenty ", "Thirty ", "Forty ", "Fifty ", "Sixty ", "Seventy ", "Eighty ", "Ninety "
};

int main()
{
    long num;

    printf("Enter a number (max 9 digits): ");
    scanf("%ld", &num);

    if (num <= 0)
    {
        printf("Zero\n");
    }
    else
    {
        printf("In words: ");
        // Indian System: Crore, Lakh, Thousand, Hundred
        convert((num / 10000000), "Crore ");
        convert(((num / 100000) % 100), "Lakh ");
        convert(((num / 1000) % 100), "Thousand ");
        convert(((num / 100) % 10), "Hundred ");
        convert((num % 100), "");
        printf("\n");
    }

    return 0;
}

void convert(long n, char *suffix)
{
    if (n > 19)
    {
        printf("%s%s", ten[n / 10], one[n % 10]);
    }
    else
    {
        printf("%s", one[n]);
    }

    if (n > 0)
    {
        printf("%s", suffix);
    }
}