luc035.c

Problem Statement

luc035.c

According to a study, the approximate level of intelligence of a person can be calculated using the following formula. i = 2 + (y + 0.5x) write a program that will produce a table of values of i, y and x, where y varies from 1 to 6, and, for each value of y, x varies from 5.5 to 12.5 in steps of 0.5

Source Code

#include <stdio.h>
int main()
{
    double y, x;
    printf("\n--- Approximate Intelligence ---\n");
    for (y = 1; y <= 6; y++)
    {
        printf("\tY = %d\n", y);
        for (x = 5.5; x <= 12.5; x += 0.5)
        {
            printf("Y: %g\t X: %.2g\t I: %g\n", y, x, 2 + (y + 0.5 * x));
        }
        printf("-----------------------\n");
    }
    return 0;
}

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● Author - Amit Dutta · Updated - 12 Dec 2025