apc-prac-037.c¶
Problem Statement
Show all the armstrong number between a range.
Metadata¶
| Property | Detail |
|---|---|
| Author | Amit Dutta amitdutta4255@gmail.com |
| Date | 12 Dec 2025 |
| License | MIT License (See the LICENSE file for details) |
Actions¶
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Source Code¶
#include <stdio.h>
#include <math.h>
#define lowerBound 100
#define upperBound 999
int isArmstrongNumber(int);
int isArmstrongNumber(int n)
{
int temp = n, sum = 0, count = 0;
while (temp > 0)
{
count++;
temp /= 10;
}
temp = n;
while (temp > 0)
{
sum += (int)pow(temp % 10, count);
temp /= 10;
}
return sum == n;
}
int main()
{
int n, i, count = 0;
printf("Armstrong number between %d and %d are: ", lowerBound, upperBound);
for (i = lowerBound; i <= upperBound; i++)
if (isArmstrongNumber(i))
{
printf("%d ", i);
count++;
}
printf("\n\nCount: %d\n", count);
return 0;
}